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在Java中,我们如何在JSON序列化过程中忽略某些字段?

如果Java对象中存在不希望被序列化的字段,我们可以使用 @JsonIgnore注解 在 Jackson 库中。在 序列化 和 反序列化 期间, @JsonIgnore 可以用于忽略字段。 Find JSON Path Online Easily find JSON paths within JSON objects using our intuitive Json Path Finder 下载 语法
public @interface JsonIgnore
示例
import java.io.*; import java.util.*; import com.fasterxml.jackson.core.*; import com.fasterxml.jackson.databind.*; import com.fasterxml.jackson.annotation.*; public class JsonIgnoreAnnotationTest { public static void main(String args[]) throws JsonGenerationException, JsonMappingException, IOException { Employee emp = new Employee(); emp.setFirstName("Raja"); emp.setLastName("Ramesh"); emp.setEmpId(120); emp.getTechnologies().add("Java"); emp.getTechnologies().add("Scala"); emp.getTechnologies().add("Python"); ObjectMapper mapper = new ObjectMapper(); mapper.writerWithDefaultPrettyPrinter().writeValue(System.out, emp); } } // Employee class @JsonInclude(JsonInclude.Include.NON_NULL) @JsonPropertyOrder({ "firstName", "lastName", "technologies", "empId" }) class Employee { @JsonProperty("EMPLOYEE_ID") private int empId; @JsonProperty("EMPLOYEE_FIRST_NAME") private String firstName; @JsonProperty("EMPLOYEE_LAST_NAME") private String lastName; @JsonIgnore private List technologies = new ArrayList<>(); public int getEmpId() { return empId; } public void setEmpId(int empId) { this.empId = empId; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public List getTechnologies() { return technologies; } public void setTechnologies(List technologies) { this.technologies = technologies; } }
输出
{ "EMPLOYEE_FIRST_NAME" : "Raja", "EMPLOYEE_LAST_NAME" : "Ramesh", "EMPLOYEE_ID" : 120 }

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