图片和二进制之间的转换
将图片转换成二进制保存在数据库中，代码如下：
if($_FILES['image']['size'])
{
$names=$_FILES['image']['name'];
$arr=explode('.',$names);
$name=$arr[0];
$date=date('Y-m-d h:i:s');
$fp = fopen($_FILES['image']['tmp_name'], 'rb');
$type = $_FILES['image']['type'];
if (!$fp) {
echo('读取图片失败！');
} else {
$image = addslashes(fread($fp, filesize($_FILES['image']['tmp_name'])));
if ($image) {
$pic=new Image();
$pic->name=$name;
$pic->pic=$image;
$pic->type=$type;
$pic->date=$date;
if($pic->save())
{
$this->flash->notice("图片保存成功");
}
}
}
}
图片保存到数据库中了，文件的格式是BLOB，但是我从数据库中查找到并输出的时候是乱码，代码如下：
$conn=mysqli_connect("localhost","root","");
if(!$conn)
{
$this->flash->notice("连接失败");
}
else
{
mysqli_select_db($conn,"");
$result = mysqli_query($conn,"select * from image where id=3");
if(!$result)
{
$this->flash->notice("数据不存在");
}
else
{
$data=mysqli_fetch_row($result);
/*$type=$data[3];
Header("Content-type: $type");*/
echo($data[2]);
我应该怎么去转换成图片并显示出来呢？求大神帮忙
------解决思路----------------------
写了一个完整的例子，可以参考下。
数据表结构
upload_image_todb.php
CREATE TABLE `photo` (
`id` int(10) unsigned NOT NULL auto_increment,
`type` varchar(100) NOT NULL,
`photo` mediumblob NOT NULL,
PRIMARY KEY (`id`)
)
[email protected]_connect("数据库ip","帐号","密码") or die(mysql_error());
@mysql_select_db('数据库名',$conn) or die(mysql_error());
$action = isset($_REQUEST['action'])? $_REQUEST['action'] : '';
if($action=='add'){
$image = mysql_escape_string(file_get_contents($_FILES['photo']['tmp_name']));
$type = $_FILES['photo']['type'];
$sqlstr = "insert into photo(type,photo) values('".$type."','".$image."')";
@mysql_query($sqlstr) or die(mysql_error());
header('location:upload_image_todb.php');
}elseif($action=='show'){
$id = isset($_GET['id'])? intval($_GET['id']) : 0;