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C语言圣诞树的实现示例

你们要的圣诞树它来啦!

快去送给心爱的人吧!

效果如下:

#define _CRT_SECURE_NO_WARNINGS 1#include #include #include #include

#define PI 3.14159265359f

float sx, sy;

typedef float Mat[4][4];typedef float Vec[4];

void scale(Mat* m, float s) {Mat temp = { {s,0,0,0}, {0,s,0,0 }, { 0,0,s,0 }, { 0,0,0,1 } };memcpy(m, &temp, sizeof(Mat));}

void rotateY(Mat* m, float t) {float c = cosf(t), s = sinf(t);Mat temp = { {c,0,s,0}, {0,1,0,0}, {-s,0,c,0}, {0,0,0,1} };memcpy(m, &temp, sizeof(Mat));}

void rotateZ(Mat* m, float t) {float c = cosf(t), s = sinf(t);Mat temp = { {c,-s,0,0}, {s,c,0,0}, {0,0,1,0}, {0,0,0,1} };memcpy(m, &temp, sizeof(Mat));}

void translate(Mat* m, float x, float y, float z) {Mat temp = { {1,0,0,x}, {0,1,0,y}, {0,0,1,z}, {0,0,0,1} };memcpy(m, &temp, sizeof(Mat));}

void mul(Mat* m, Mat a, Mat b) {Mat temp;for (int j = 0; j < 4; j++) for (int i = 0; i < 4; i++) {temp[j][i] = 0.0f;for (int k = 0; k < 4; k++) temp[j][i] += a[j][k] * b[k][i];}memcpy(m, &temp, sizeof(Mat));}

void transformPosition(Vec* r, Mat m, Vec v) {Vec temp = { 0, 0, 0, 0 };for (int j = 0; j < 4; j++) for (int i = 0; i < 4; i++) temp[j] += m[j][i] * v[i];memcpy(r, &temp, sizeof(Vec));}

float transformLength(Mat m, float r) {return sqrtf(m[0][0] * m[0][0] + m[0][1] * m[0][1] + m[0][2] * m[0][2]) * r;}

float sphere(Vec c, float r) {float dx = c[0] - sx, dy = c[1] - sy;float a = dx * dx + dy * dy;return a < r* r ? sqrtf(r * r - a) + c[2] : -1.0f;}

float opUnion(float z1, float z2) {return z1 > z2 ? z1 : z2;}

float f(Mat m, int n) {float z = -1.0f;for (float r = 0.0f; r < 0.8f; r += 0.02f) {Vec v = { 0.0f, r, 0.0f, 1.0f };transformPosition(&v, m, v);z = opUnion(z, sphere(v, transformLength(m, 0.05f * (0.95f - r))));}

if (n > 0) {Mat ry, rz, s, t, m2, m3;rotateZ(&rz, 1.8f);

for (int p = 0; p < 6; p++) {rotateY(&ry, p * (2 * PI / 6));mul(&m2, ry, rz);float ss = 0.45f;for (float r = 0.2f; r < 0.8f; r += 0.1f) {scale(&s, ss);translate(&t, 0.0f, r, 0.0f);mul(&m3, s, m2);mul(&m3, t, m3);mul(&m3, m, m3);z = opUnion(z, f(m3, n - 1));ss *= 0.8f;}}}

return z;}

float f0(float x, float y, int n) {sx = x;sy = y;Mat m;scale(&m, 1.0f);return f(m, n);}

int main(int argc, char* argv[]) {//这个里可以加打印信息哟,为他添加专属的printf

int n = argc > 1 ? atoi(argv[1]) : 3;float zoom = argc > 2 ? atof(argv[2]) : 1.0f;for (float y = 0.8f; y > -0.0f; y -= 0.02f / zoom, putchar('\n')) for (float x = -0.35f; x < 0.35f; x += 0.01f / zoom) {float z = f0(x, y, n);if (z > -1.0f) {float nz = 0.001f;float nx = f0(x + nz, y, n) - z;float ny = f0(x, y + nz, n) - z;float nd = sqrtf(nx * nx + ny * ny + nz * nz);float d = (nx - ny + nz) / sqrtf(3) / nd;d = d > 0.0f ? d : 0.0f;// d = d < 1.0f ? d : 1.0f;putchar(".-:=+*#%@@"[(int)(d * 9.0f)]);}else putchar(' ');}}到此这篇关于C语言圣诞树的实现示例的文章就介绍到这了,更多相关C语言 圣诞树内容请搜索脚本之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持脚本之家!

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